18y^2+15y-3=0

Solution for 18y^2+15y-3=0 equation:

18y^2+15y-3=0

a = 18; b = 15; c = -3;
Δ = b2-4ac
Δ = 152-4·18·(-3)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-21}{2*18}=\frac{-36}{36}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+21}{2*18}=\frac{6}{36}
=1/6
$